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大学教师,环评工程师,从事环境影响评价的教学和科研工作。 联系方式:xuson@yeah.net

08年技术方法一道考题的解答  

2010-06-19 20:45:42|  分类: 环评考试 |  标签: |举报 |字号 订阅

  下载LOFTER 我的照片书  |
  近日有几位考生问了一道08年(是否该年考题没有考证)技术方法的题目,现解答如下:

一、题目

某电镀企业使用ZnCl2作原料,已知年耗ZnCl2100t(折纯);98.0%的锌进入电镀产品,1.90%的锌进入固体废物,剩余的锌全部进入废水中;废水排放量15000m3/a,废水中总锌的浓度为(   )。(Zn原子量:65.4Cl原子量:35.5

A0.8mg/L          B1.6mg/L

B3.2mg/L          D4.8mg/L

 

二、解答

(1)首先要计算锌在原材料的换算值

08年技术方法一道考题的解答 - 徐 颂 - 徐颂的博客

 

2)年耗ZnCl2100t锌的含量

100t×48.3%=48.3(t)

(3) 锌进入废水的量

48.3(t) ×1-98.0%-1.90%=48.3(t) ×0.1%=0.0483(t)

(4) 废水中总锌的浓度的计算

08年技术方法一道考题的解答 - 徐 颂 - 徐颂的博客

三、题后语

1、此题为工程分析中“物料衡算”计算源强的典型题,不算难。第1步是关键。

2、解题思路是:要算浓度值,肯定要知道锌的量,锌的量则从物料衡算中求出。

3、从解题技巧上看,做到第3步时,不需单位换算,经简单计算就可选择答案了,会节省一些时间。当然,如果此题放在案例题中,则单位换算是要精确的。

4、“物料衡算”在教材中谁都看得懂,但很多考生没有理解其精髓,遇得问题却不知如何解答,说明其未真正懂。原理弄懂了,万变不离其宗。

52010年版《环境影响评价技术方法基础过关800题》中第3页也有类似题。

   以上解答纯属个人理解,非标准答案,如需转载,请注明出处。
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